此种进入4号房间的方法我也曾经用                                                             过,靠时间来判断是否到了4号房间并不可靠,

本人就曾经栽在这种方法上,不建议使用此种方法 */

                }

            }

            else

            {

                if(gi_1 == 2)

                {

                    drive( 0 , 80);      /*右转180*/

                    wait( 0.650000 );

                    stop();

                    gi_1 = 3 ;

                }

                else

                {

                    if(gi_1 == 3)

                    {

                        SubRoutine_1 ();   /*继续左手走,进入4号房间*/

                       

                    }

                }

            }

            photo_1 =photo(1);                      /*检测左眼的亮度*/

            photo_2 =photo(2);                      /*